What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t[]={3,2,4,1,5,6,10,8,7,9}; vector for_each(v1.begin(), v1.end(), bind1st(plus for_each(v1.rbegin(), v1.rend(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
int main ()
{
std::vector
for(int i = 10; i>0; i??)
{
v1.push_back(i);
}
std::vector
int sum = 0;
while(it != v1.end())
{
sum+=it++;
}
std::cout<<*v1.erase(v1.begin(),v1.end()?3)<<" "< return 0; }
What happens when you attempt to compile and run the following code? Choose all that apply.
#include
#include
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) {out< int main () { int t[] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; fstream f("test.out", ios::trunc|ios::out); list for_each(l.begin(), l.end(), Out f.close(); f.open("test.out"); for( ; f.good() ; ) { int i; f>>i; cout< } f.close(); return 0; }
Which method added to class B at the marked spot will allow the code below to compile? Choose all possible solutions.
#include
#include
#include
using namespace std;
class B { int val;
public:
B(int v):val(v){}
int getV() const {return val;}
/* Insert Code Here */
};
ostream & operator <<(ostream & out, const B & v) { out< template ostream & out; Out(ostream & o): out(o){} void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; vector v1(t, t+10); sort(v1.begin(), v1.end(), greater()); for_each(v1.begin(), v1.end(), Out(cout));cout< return 0; }
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={3,2,4,1,5}; int t2[]={6,10,8,7,9}; vector transform(t1,t1+5,t2,v1.rbegin(), plus for_each(v1.rbegin(), v1.rend(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
int main() {
int t[] = { 10, 5, 9, 6, 2, 4, 7, 8, 3, 1 };
map
for(int i=0; i < 10; i++) {
m[i]=t[i];
}
pair
map
if (it != m.end())
{
cout< } else { cout<<"Not found!\n"; } return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t1[]={3,2,4,1,5}; int t2[]={6,10,8,7,9}; vector sort(t1, t1+5); sort(t2, t2+5); copy(t1,t1+5,v1.begin()); copy(t2,t2+5,v1.begin()+5); merge(v1.begin(), v1.begin()+5,v1.end()); for_each(v1.begin(), v1.end(), Out return 0; } Program outputs:
What happens when you attempt to compile and run the following code?
#include
#include
#include
#include
using namespace std;
template
ostream & out;
Out(ostream & o): out(o){}
void operator() (const T & val ) { out< int main() { int t[]={8, 10, 5, 1, 4, 6, 2, 7, 9, 3}; deque set cout< return 0; } Choose all possible outputs (all that apply):